D2P2 in ysh

2023/2/2/puzzle.md

@@ -0,0 +1,71 @@
+\--- Day 2: Cube Conundrum ---
+----------
+
+You're launched high into the atmosphere! The apex of your trajectory just barely reaches the surface of a large island floating in the sky. You gently land in a fluffy pile of leaves. It's quite cold, but you don't see much snow. An Elf runs over to greet you.
+
+The Elf explains that you've arrived at *Snow Island* and apologizes for the lack of snow. He'll be happy to explain the situation, but it's a bit of a walk, so you have some time. They don't get many visitors up here; would you like to play a game in the meantime?
+
+As you walk, the Elf shows you a small bag and some cubes which are either red, green, or blue. Each time you play this game, he will hide a secret number of cubes of each color in the bag, and your goal is to figure out information about the number of cubes.
+
+To get information, once a bag has been loaded with cubes, the Elf will reach into the bag, grab a handful of random cubes, show them to you, and then put them back in the bag. He'll do this a few times per game.
+
+You play several games and record the information from each game (your puzzle input). Each game is listed with its ID number (like the `11` in `Game 11: ...`) followed by a semicolon-separated list of subsets of cubes that were revealed from the bag (like `3 red, 5 green, 4 blue`).
+
+For example, the record of a few games might look like this:
+
+```
+Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green
+Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue
+Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red
+Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red
+Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green
+
+```
+
+In game 1, three sets of cubes are revealed from the bag (and then put back again). The first set is 3 blue cubes and 4 red cubes; the second set is 1 red cube, 2 green cubes, and 6 blue cubes; the third set is only 2 green cubes.
+
+The Elf would first like to know which games would have been possible if the bag contained *only 12 red cubes, 13 green cubes, and 14 blue cubes*?
+
+In the example above, games 1, 2, and 5 would have been *possible* if the bag had been loaded with that configuration. However, game 3 would have been *impossible* because at one point the Elf showed you 20 red cubes at once; similarly, game 4 would also have been *impossible* because the Elf showed you 15 blue cubes at once. If you add up the IDs of the games that would have been possible, you get `*8*`.
+
+Determine which games would have been possible if the bag had been loaded with only 12 red cubes, 13 green cubes, and 14 blue cubes. *What is the sum of the IDs of those games?*
+
+Your puzzle answer was `2727`.
+
+\--- Part Two ---
+----------
+
+The Elf says they've stopped producing snow because they aren't getting any *water*! He isn't sure why the water stopped; however, he can show you how to get to the water source to check it out for yourself. It's just up ahead!
+
+As you continue your walk, the Elf poses a second question: in each game you played, what is the *fewest number of cubes of each color* that could have been in the bag to make the game possible?
+
+Again consider the example games from earlier:
+
+```
+Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green
+Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue
+Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red
+Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red
+Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green
+
+```
+
+* In game 1, the game could have been played with as few as 4 red, 2 green, and 6 blue cubes. If any color had even one fewer cube, the game would have been impossible.
+* Game 2 could have been played with a minimum of 1 red, 3 green, and 4 blue cubes.
+* Game 3 must have been played with at least 20 red, 13 green, and 6 blue cubes.
+* Game 4 required at least 14 red, 3 green, and 15 blue cubes.
+* Game 5 needed no fewer than 6 red, 3 green, and 2 blue cubes in the bag.
+
+The *power* of a set of cubes is equal to the numbers of red, green, and blue cubes multiplied together. The power of the minimum set of cubes in game 1 is `48`. In games 2-5 it was `12`, `1560`, `630`, and `36`, respectively. Adding up these five powers produces the sum `*2286*`.
+
+For each game, find the minimum set of cubes that must have been present. *What is the sum of the power of these sets?*
+
+Your puzzle answer was `56580`.
+
+Both parts of this puzzle are complete! They provide two gold stars: \*\*
+
+At this point, you should [return to your Advent calendar](/2023) and try another puzzle.
+
+If you still want to see it, you can [get your puzzle input](2/input).
+
+You can also [Shareon [Twitter](https://twitter.com/intent/tweet?text=I%27ve+completed+%22Cube+Conundrum%22+%2D+Day+2+%2D+Advent+of+Code+2023&url=https%3A%2F%2Fadventofcode%2Ecom%2F2023%2Fday%2F2&related=ericwastl&hashtags=AdventOfCode) [Mastodon](javascript:void(0);)] this puzzle.

2023/2/2/puzzle.txt

@@ -1,34 +0,0 @@
---- Part Two ---
-
-The Elf says they've stopped producing snow because they aren't getting any
-water! He isn't sure why the water stopped; however, he can show you how to get
-to the water source to check it out for yourself. It's just up ahead!
-
-As you continue your walk, the Elf poses a second question: in each game you
-played, what is the fewest number of cubes of each color that could have been in
-the bag to make the game possible?
-
-Again consider the example games from earlier:
-
-Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green
-Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue
-Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red
-Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red
-Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green
-
-In game 1, the game could have been played with as few as 4 red, 2 green, and 6
-blue cubes. If any color had even one fewer cube, the game would have been
-impossible.
-
-Game 2 could have been played with a minimum of 1 red, 3 green, and 4 blue cubes.
-Game 3 must have been played with at least 20 red, 13 green, and 6 blue cubes.
-Game 4 required at least 14 red, 3 green, and 15 blue cubes.
-Game 5 needed no fewer than 6 red, 3 green, and 2 blue cubes in the bag.
-
-The power of a set of cubes is equal to the numbers of red, green, and blue
-cubes multiplied together. The power of the minimum set of cubes in game 1 is
-48. In games 2-5 it was 12, 1560, 630, and 36, respectively. Adding up these
-five powers produces the sum 2286.
-
-For each game, find the minimum set of cubes that must have been present. What
-is the sum of the power of these sets?

2023/2/2/solution.sh

@@ -1,13 +1,13 @@
 #!/usr/bin/env bash
 
-#set -o errexit
+set -o errexit
 set -o nounset
-#set -o pipefail
+set -o pipefail
 if [[ "${TRACE-0}" == "1" ]]; then
   set -o xtrace
 fi
 
-cd "$(dirname "$0")"
+INPUT=$1
 
 main ()
 {
@@ -19,14 +19,14 @@ main ()
     IFS=';' read -r -a sets <<< "${stripped_game}"
     for (( i=0; i<${#sets[@]}; i++ )); do
       for color in "${colors[@]}"; do
-        count=$(grep -o "[0-9]* ${color}" <<< "${sets[$i]}" | grep -o '[0-9]*')
+        count=$(grep -o "[0-9]* ${color}" <<< "${sets[$i]}" | grep -o '[0-9]*' || true)
         if [[ $count -gt ${colors_max[$color]} ]]; then
           colors_max[$color]=$count
         fi
       done
     done
     (( powers+=colors_max[red]*colors_max[green]*colors_max[blue] ))
-  done < input.txt
+  done < ${INPUT}
   echo $powers
 }
 

2023/2/2/solution.ysh.sh

@@ -0,0 +1,27 @@
+#!/usr/bin/env ysh
+
+const INPUT = $1
+
+proc main {
+  var powers = 0
+  while read -r game {
+    var colors = {'red': 0, 'green': 0, 'blue': 0}
+    var sets = game=>split(':')[1]
+    setvar sets = sets=>split(';')
+    for i in (0 .. len(sets)) {
+      for color in (colors->keys()) {
+        var pair = $(grep -o "[0-9]* ${color}" <<< $[sets[i]] || true)
+        if (len(pair) !== 0) {
+          var count = int(pair=>split()[0])
+          if (count > colors[color]) {
+            setvar colors[color] = count
+          }
+        }
+      }
+    }
+    setvar powers += colors['red'] * colors['green'] * colors['blue']
+  } < ${INPUT}
+  echo ${powers}
+}
+
+main