D2P1 in ysh
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2023/2/1/puzzle.md
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2023/2/1/puzzle.md
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\--- Day 2: Cube Conundrum ---
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----------
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You're launched high into the atmosphere! The apex of your trajectory just barely reaches the surface of a large island floating in the sky. You gently land in a fluffy pile of leaves. It's quite cold, but you don't see much snow. An Elf runs over to greet you.
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The Elf explains that you've arrived at *Snow Island* and apologizes for the lack of snow. He'll be happy to explain the situation, but it's a bit of a walk, so you have some time. They don't get many visitors up here; would you like to play a game in the meantime?
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As you walk, the Elf shows you a small bag and some cubes which are either red, green, or blue. Each time you play this game, he will hide a secret number of cubes of each color in the bag, and your goal is to figure out information about the number of cubes.
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To get information, once a bag has been loaded with cubes, the Elf will reach into the bag, grab a handful of random cubes, show them to you, and then put them back in the bag. He'll do this a few times per game.
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You play several games and record the information from each game (your puzzle input). Each game is listed with its ID number (like the `11` in `Game 11: ...`) followed by a semicolon-separated list of subsets of cubes that were revealed from the bag (like `3 red, 5 green, 4 blue`).
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For example, the record of a few games might look like this:
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```
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Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green
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Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue
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Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red
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Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red
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Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green
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```
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In game 1, three sets of cubes are revealed from the bag (and then put back again). The first set is 3 blue cubes and 4 red cubes; the second set is 1 red cube, 2 green cubes, and 6 blue cubes; the third set is only 2 green cubes.
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The Elf would first like to know which games would have been possible if the bag contained *only 12 red cubes, 13 green cubes, and 14 blue cubes*?
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In the example above, games 1, 2, and 5 would have been *possible* if the bag had been loaded with that configuration. However, game 3 would have been *impossible* because at one point the Elf showed you 20 red cubes at once; similarly, game 4 would also have been *impossible* because the Elf showed you 15 blue cubes at once. If you add up the IDs of the games that would have been possible, you get `*8*`.
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Determine which games would have been possible if the bag had been loaded with only 12 red cubes, 13 green cubes, and 14 blue cubes. *What is the sum of the IDs of those games?*
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Your puzzle answer was `2727`.
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\--- Part Two ---
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----------
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The Elf says they've stopped producing snow because they aren't getting any *water*! He isn't sure why the water stopped; however, he can show you how to get to the water source to check it out for yourself. It's just up ahead!
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As you continue your walk, the Elf poses a second question: in each game you played, what is the *fewest number of cubes of each color* that could have been in the bag to make the game possible?
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Again consider the example games from earlier:
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```
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Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green
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Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue
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Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red
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Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red
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Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green
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```
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* In game 1, the game could have been played with as few as 4 red, 2 green, and 6 blue cubes. If any color had even one fewer cube, the game would have been impossible.
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* Game 2 could have been played with a minimum of 1 red, 3 green, and 4 blue cubes.
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* Game 3 must have been played with at least 20 red, 13 green, and 6 blue cubes.
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* Game 4 required at least 14 red, 3 green, and 15 blue cubes.
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* Game 5 needed no fewer than 6 red, 3 green, and 2 blue cubes in the bag.
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The *power* of a set of cubes is equal to the numbers of red, green, and blue cubes multiplied together. The power of the minimum set of cubes in game 1 is `48`. In games 2-5 it was `12`, `1560`, `630`, and `36`, respectively. Adding up these five powers produces the sum `*2286*`.
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For each game, find the minimum set of cubes that must have been present. *What is the sum of the power of these sets?*
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Your puzzle answer was `56580`.
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Both parts of this puzzle are complete! They provide two gold stars: \*\*
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At this point, you should [return to your Advent calendar](/2023) and try another puzzle.
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If you still want to see it, you can [get your puzzle input](2/input).
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You can also [Shareon [Twitter](https://twitter.com/intent/tweet?text=I%27ve+completed+%22Cube+Conundrum%22+%2D+Day+2+%2D+Advent+of+Code+2023&url=https%3A%2F%2Fadventofcode%2Ecom%2F2023%2Fday%2F2&related=ericwastl&hashtags=AdventOfCode) [Mastodon](javascript:void(0);)] this puzzle.
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@ -1,51 +0,0 @@
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--- Day 2: Cube Conundrum ---
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You're launched high into the atmosphere! The apex of your trajectory just
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barely reaches the surface of a large island floating in the sky. You gently
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land in a fluffy pile of leaves. It's quite cold, but you don't see much snow.
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An Elf runs over to greet you.
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The Elf explains that you've arrived at Snow Island and apologizes for the lack
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of snow. He'll be happy to explain the situation, but it's a bit of a walk, so
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you have some time. They don't get many visitors up here; would you like to play
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a game in the meantime?
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As you walk, the Elf shows you a small bag and some cubes which are either red,
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green, or blue. Each time you play this game, he will hide a secret number of
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cubes of each color in the bag, and your goal is to figure out information about
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the number of cubes.
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To get information, once a bag has been loaded with cubes, the Elf will reach
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into the bag, grab a handful of random cubes, show them to you, and then put
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them back in the bag. He'll do this a few times per game.
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You play several games and record the information from each game (your puzzle
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input). Each game is listed with its ID number (like the 11 in Game 11: ...)
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followed by a semicolon-separated list of subsets of cubes that were revealed
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from the bag (like 3 red, 5 green, 4 blue).
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For example, the record of a few games might look like this:
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Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green
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Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue
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Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red
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Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red
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Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green
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In game 1, three sets of cubes are revealed from the bag (and then put back
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again). The first set is 3 blue cubes and 4 red cubes; the second set is 1 red
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cube, 2 green cubes, and 6 blue cubes; the third set is only 2 green cubes.
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The Elf would first like to know which games would have been possible if the bag
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contained only 12 red cubes, 13 green cubes, and 14 blue cubes?
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In the example above, games 1, 2, and 5 would have been possible if the bag had
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been loaded with that configuration. However, game 3 would have been impossible
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because at one point the Elf showed you 20 red cubes at once; similarly, game 4
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would also have been impossible because the Elf showed you 15 blue cubes at
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once. If you add up the IDs of the games that would have been possible, you get
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8.
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Determine which games would have been possible if the bag had been loaded with
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only 12 red cubes, 13 green cubes, and 14 blue cubes. What is the sum of the IDs
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of those games?
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@ -1,13 +1,13 @@
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#!/usr/bin/env bash
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#set -o errexit
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set -o errexit
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set -o nounset
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#set -o pipefail
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set -o pipefail
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if [[ "${TRACE-0}" == "1" ]]; then
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set -o xtrace
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fi
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cd "$(dirname "$0")"
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INPUT=$1
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main ()
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{
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@ -20,9 +20,10 @@ main ()
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IFS=';' read -r -a sets <<< "${stripped_game}"
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for (( i=0; i<${#sets[@]}; i++ )); do
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for color in "${colors[@]}"; do
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count=$(grep -o "[0-9]* ${color}" <<< "${sets[$i]}" | grep -o '[0-9]*')
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count=$(grep -o "[0-9]* ${color}" <<< "${sets[$i]}" | grep -o '[0-9]*' || true)
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if [[ $count -gt ${limits[$color]} ]]; then
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possible=false
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break 2
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fi
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done
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done
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@ -30,7 +31,7 @@ main ()
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id=$(grep -o '[0-9]*' <<< "${game}" | head -n 1)
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possible_ids+=($id)
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fi
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done < input.txt
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done < "${INPUT}"
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declare -i sum=0
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for id in "${possible_ids[@]}"; do
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(( sum+=id ))
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35
2023/2/1/solution.ysh.sh
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35
2023/2/1/solution.ysh.sh
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#!/usr/bin/env ysh
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source --builtin list.ysh # sum()
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const INPUT = $1
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const COLORS = {'red': 12, 'green': 13, 'blue': 14}
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proc main {
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var possible_ids = []
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while read -r game {
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var possible = true
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var sets = game=>split(':')[1]
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setvar sets = sets=>split(';')
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for i in (0 .. len(sets)) {
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for color in (COLORS->keys()) {
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var pair = $(grep -o "[0-9]* ${color}" <<< $[sets[i]] || true)
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if (len(pair) !== 0) {
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var count = int(pair=>split()[0])
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if (count > COLORS[color]) {
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setvar possible = false
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break 2
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}
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}
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}
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}
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if (possible) {
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var id = game=>split(':')[0]
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setvar id = id=>split()[1]
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call possible_ids->append(id)
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}
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} < ${INPUT}
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echo $[sum(possible_ids)]
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}
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main
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